ⓘ 1896 United States presidential election in Rhode Island

                                     

ⓘ 1896 United States presidential election in Rhode Island

The 1896 United States presidential election in Rhode Island took place on November 3, 1896. Voters chose 4 representatives, or electors to the Electoral College, who voted for president and vice president.

Rhode island voted for the Republican candidate, former Governor of Ohio William McKinley, over the Democratic candidate, former U.S. representative from Nebraska, William Jennings Bryan. McKinley won by a large margin from 41.94%.

Brian, running on a platform of free silver, called the Western miners and farmers in the election of 1896, but there is little appeal in the North-Eastern States like Rhode island.

With 68.33% of the vote, the state of Rhode island will be the fourth strongest McKinleys victory percentage in the popular vote after Vermont, neighboring Massachusetts and new Hampshire.