ⓘ 1992 United States presidential election in Vermont

                                     

ⓘ 1992 United States presidential election in Vermont

The 1992 United States presidential election in Vermont took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont won the Governor from the Democratic party, bill Clinton from Arkansas, taking 46.11 percent of votes for the incumbent Republican President George Bush from Texas, who took 30.42%, a victory margin of 15.69%. Independent Texas billionaire Ross Perot finished in third place, with 22.78% of the votes. Clinton ultimately won the popular vote, defeating incumbent President Bush.

These elections will be re-alignment to Vermont. The Clintons decisive double-digit victory in the state, including the Democratic sweep of all 14 districts was a significant improvement for the state, which up to this point has been reliably Republican for more than 130 years. It was only the second time in history that a democratic presidential candidate in the US won Vermonts votes, the first and only until the time when Lyndon Johnson moved the state in the 1964 Democratic landslide. Except for 1964, Vermont has voted Republican in all presidential elections from 1856 to 1988. Since 1992, however, Vermont became reliably democratic state in presidential elections, vote for the Democrat in every election that followed.

Vermonts sudden departure from the Republican party was largely the product of drastic changes within the party. In 1990-e years, the Republican party, which once was a bright progressive North-East wing was almost completely passed into the hands of conservatives, southerners, Evangelical Christians. Consequently, a Vermont liberal and secular New England States, moved to a more democratic party, and is today considered one of the safest blue States.

                                     
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