ⓘ 1992 United States presidential election in Nevada

                                     

ⓘ 1992 United States presidential election in Nevada

The 1992 United States presidential election in Nevada took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Nevada was won by Governor bill Clinton D-Arkansas with 37.36% of the vote, over incumbent President George Bush, R-Texas, with 34.73%. Businessman Ross Perot I-Texas finished third with 26.19% of votes. Clinton ultimately won the popular vote, defeating incumbent President Bush and Perot.

The Clintons win, albeit narrow, will be the beginning of the transition of Nevada from a safe Republican state in swing States in all three presidential elections held in 1980-ies, the Republicans dominated the Nevada two-digit field and swept every County. Although Clinton carried only two States seventeen counties, a victory in Clark County where it is located in Las Vegas, and the most populous County in the state, will be key to this and future democratic victories in Nevada.

Clinton percentage of the vote was the lowest gain state with Woodrow Wilson is Idaho, only 31 percent of the vote in 1912.

As the presidential election of 2016, this is the last time a presidential candidate from the Democratic party carried the County white pine in the presidential election, and the last where the third-party candidate carried any Nevada County. In this case, Ross Perot carried a storey County.

                                     
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